E=mc² - Einstein Marathon 2008

,

Hello my friends,

I'm very sorry I didn't write a new blog posting for such a long time. Unfortunately I was very busy in this time.
I only did some silent (but huge) CSS updates in January. Because there I migrate to the new my.opera "template/sample" (maybe wrong words) after the big my.opera update in January. (It was a good timing to migrate my CSS on that time I think). I also fixed a lot of bugs and cleaned the CSS a little bit. When I have more time I will clean my CSS more, because so far I still have more than 1600 lines of CSS code. idea

But now back to the topic I wanna talk about today. smile Some of my colleagues talked about the Einstein marathon some weeks ago. That's a marathon which takes place in Ulm and Neu Ulm, the birthplace of Albert Einstein. The Einstein marathon was founded in 2005 because there was the "World Year of Physics".
The marathon is very famous here now. My colleagues asked others if someone would join that event as well. They got much feedback. Also from much beginners, so they decided to join the half marathon as a group of colleagues.
Last months I often thought I should do more sports again. I didn't really go jogging, had no time for sport or other things. In short words: I definitely need more fitness... rolleyes
So I think to aim at doing something is a good idea.
And why not to join a (half) marathon? So I decided I will start training soon. From next week I will go jogging after work with some colleagues every week. (OK, I try it). I will also try to do much more at home.

By the way, the marathon takes place in September, so I still have enough time for training. Well I hope I can do training beside my busy time. But I'm optimistic.
So let's start soon. bigsmile

Best wishes,
Heiko

I'm backMember of the week

Comments

-demiphonic Tuesday, March 18, 2008 12:33:48 AM

if you find an 1/8 marathons count me in rolleyes p

Heiko WagnerRyuu Tuesday, March 18, 2008 8:50:25 PM

Hello Randall,
then you should come to Germany. Because at the Einstein marathon there is also a 10km and 5km sprint course available. Last one would be roughly a 1/8 marathon. p So I count you in. bigsmile

Best wishes,
Heiko

-demiphonic Wednesday, March 19, 2008 1:37:19 AM

dang irked *I should have said 1/16 faint*

lol!! p

Chu Yuhozariski Wednesday, March 19, 2008 3:33:49 PM

Hi, Heiko. Welcome back. smile

I have an experience participating a full course marathon in 2005, but the record was very bad. It was almost 5 hours. p

Good luck to you. up

Heiko WagnerRyuu Wednesday, March 19, 2008 6:41:17 PM

bigsmile Sounds like a pretext/excuse, Randall! lol
New motto: Randall for presi... ehmm marathon! idea

Best wishes,
Heiko

Heiko WagnerRyuu Wednesday, March 19, 2008 6:45:31 PM

Hi 유호,
thank you very much. smile It's very interesting you also did a marathon in 2005. Very cool! up
Well I hope I find enough time for training. smile

Best wishes,
Heiko

-demiphonic Wednesday, March 19, 2008 8:41:19 PM

hehe p

Heiko WagnerRyuu Wednesday, March 19, 2008 9:34:25 PM

Hi Randall, I interpret this like a "yes". bigsmile

Best wishes,
Heiko

-demiphonic Thursday, March 20, 2008 12:32:00 AM

lol ...fat chance p lol

Antoniaantoniapril Thursday, March 20, 2008 4:18:51 AM

Hallo~ Ich wuerde seit September in HS Esslingen studieren. In welcher Stadt wohnst du? smile

Viele Gruesse,
Antonia

galadriel Thursday, March 20, 2008 9:00:21 AM

I never knew there was an Einstein marathon. Keep training and you'll be the winner bigsmile

Heiko WagnerRyuu Thursday, March 20, 2008 9:08:01 PM

Definitely, Randall. YOUR chance! lol

Best wishes,
Heiko

Heiko WagnerRyuu Thursday, March 20, 2008 9:12:51 PM

Hallo Antonia,
wow! bigeyes Das ist super! smile Ich wohne nicht so weit weg. Ich komme aus Ulm.
Welche Fachrichtung studierst du an der HS Esslingen? smile

Viele Gruesse,
Heiko

Heiko WagnerRyuu Thursday, March 20, 2008 9:19:13 PM

Hello Galadriel,
I will do training as much as possible. Well I guess there is no chance to win. bigsmile
I searched about the records of the Einstein marathon. Wow! yikes

Best wishes,
Heiko

Aprilsnow 四月雪Aprilsnow Friday, March 21, 2008 9:28:02 AM

That's a very good idea to start training early and regularly, I have never tried to run a marathon, it's not easy, I know, but good for you. up

Spring is here, I am going to do regular hiking too... hope I can condition myself for a long hike in summer time... smile

Glad you are blogging again!

Heiko WagnerRyuu Friday, March 21, 2008 2:36:07 PM

你好 Aprilsnow,
thank you very much. smile
I like hiking, too. Do you often go hiking in summer?

Best wishes. 祝你好运!
Heiko 汉克

Antoniaantoniapril Saturday, March 22, 2008 2:09:34 AM

Ich studiere Mechatronik. Du kommst aber kaum zu diesem blog..

Heiko WagnerRyuu Sunday, March 23, 2008 1:35:10 AM

Hallo Antonia,
ich wuensche dir frohe Ostern. smile

Mechatronik ist bestimmt ein sehr interessantes und vielfaeltiges Fach. Ich hoffe sehr, dass es dir hier in Deutschland auch gefaellt. smile

Leider hatte ich wirklich sehr wenig Zeit fuer meinen Blog. Das Jahr 2007 war ein sehr sehr schlechtes Jahr fuer mich...
Aber ich will mich jetzt wieder mehr auf meinen Blog konzentrieren. smile

Viele Gruesse,
Heiko

Antoniaantoniapril Tuesday, March 25, 2008 4:32:15 AM

Vielen Dank! Heiko.
Ich glaube,dass ich gut Zeit in Deutschland haben wuerde.
Warte auf deinen ausgezeichneten Blog~~

Und doch viele Gruesse in 2008:)

Heiko WagnerRyuu Tuesday, March 25, 2008 11:47:13 AM

Vielen Dank Antonia. smile
Ich glaube auch, dass du hier eine gute Zeit haben wirst. Es wird bestimmt sehr interessant und aufregend.
Wenn du Fragen hast, kannst du dich auch jederzeit bei mir melden. smile

Viele Gruesse,
Heiko

Aprilsnow 四月雪Aprilsnow Friday, March 28, 2008 7:55:53 AM

Yes, I hike in spring and fall too, in summer time I like to hike for long distance, sometimes go camping with friends in national parks, very beautiful! smile

祝你好心情!

P.S. Sorry for the late reply... wink

Heiko WagnerRyuu Friday, March 28, 2008 6:11:32 PM

你好 Aprilsnow,
don't be sorry. smile In the past, I often needed very much more time to reply. rolleyes I'm glad you like hiking, because it's very much fun.

祝你好运!
Heiko 汉克

rezadotcom Friday, April 11, 2008 6:57:25 PM

Great Design ! congrats yes

Heiko WagnerRyuu Friday, April 11, 2008 10:04:05 PM

Thanks a lot. I`m very happy you like my design. smile

Best wishes,
Heiko

rodix Saturday, April 12, 2008 1:07:34 AM

Man! Nice work!
I am amazed!
Probably the best web design I've ever seen!

May I peek around to see how was it done?

cheers Congrats!

Heiko WagnerRyuu Saturday, April 12, 2008 1:29:09 AM

Thanks a lot for your kind words. Of course you can peek around into the CSS if you want. This is no problem. smile

Best wishes,
Heiko

Unregistered user Monday, January 26, 2009 12:11:40 PM

Anonymous writes: Kepler (demolish) Vs Einstein's space jail of time r -------------- Exp (i wt) -----------S= r Exp (ì wt) Nahhas' Equation Orbit location-----------Orbit light sensing -------------- Visual orbit location Particle/Newton ---------------- --Visual -------------------------- Wave/Quantum Quantum - Newton=visual effects=relativistic effects=space-time confusions S= visual distance; r = actual distance; v = speed and c = light speed S = r Exp (i wt) = r [cosine (wt) + î sine (wt)] P =d S/d t = v Exp (ì w t) + ì r w Exp (ì w t); v=d r/d t; v=w r = v (1+ ì) [Exp (ì wt)] = visual velocity E (definition) = m/2(m v + m' r) ²; E = mc²/2 If v = 0; m' r=mc E (visual) = mp²/2 = mv²/2(1+ì) ² Exp 2(ì w t) E (visual) = mv²/2(1 + 2ì -1) [cos2wt + ì sin2wt] E (visual) = ì (mv²) [1-2sin²wt + 2i [sin (wt)] [cosine (wt)] If wt = (2n+1) π/4 E (visual) = ì (mv²) [1-1 ± ỉ] = ± (mc²); v = c 2-Central force law Areal velocity is constant: r² (d θ/d t) =h Kepler's Law h = 2π a b/T; b=a√ (1-ε²); a = mean distance value; ε = eccentricity r² (d θ/d t) = h = S² (d w/d t) Replace r with S = r exp (ỉ wt); h = [r² Exp (2iwt)] (d w/d t) (d w/d t) = (h/r²) exp [-2(i wt)] d w/d t= (h/r²) [cosine 2(wt) - ỉ sine 2(wt)] = (h/r²) [1- 2sine² (wt) - ỉ sin 2(wt)] d w/d t = d w(x)/d t + d w(y)/d t; d w(x)/d t = (h/r²) [ 1- 2sine² (wt)] d w(x)/d t – (h/r²) = - 2(h/r²)sine²(wt) = - 2(h/r²)(v/c)² v/c=sine wt (h/ r²)(Perihelion/Periastron)= [2πa.a√ (1-ε²)]/Ta² (1-ε) ²= [2π√ (1-ε²)]/T (1-ε) ² Δ w/d t = (d w/d t – h/r²] = -4π {[√ (1-ε²)]/T (1-ε) ²} (v/c) ² radian per second Δ w/d t = (- 4π /T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² radians Δ w°/d t = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² degrees; Multiplication by 180/π Δ w°/d t = (-720x36526/T) {[√ (1-ε²)]/(1-ε)²} (v/c)² degrees/100 years Δ w”/d t = (-720x3600/T) {[√ (1-ε²)]/(1-ε) ²} (v/c) ² seconds of arc multiplication by 3600 Δ w/d t = (-720x36526x3600/T) {[√ (1-ε²]/(1-ε)²} (v/c)² seconds of arc per century The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4) v=√ [G m M / (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system Application 3: Advance of Perihelion of mercury. G=6.673x10^-11; M=2x10^30kg; m=.32x10^24kg ε = 0.206; T=88days; c = 299792.458 km/sec; a = 58.2km/sec Calculations yields: v =48.14km/sec [√ (1- ε²)] (1-ε) ² = 1.552 Δ w”= (-720x36526x3600/88) x (1.552) (48.14/299792)²=43.0”/century Conclusions: E ≠ mc² (special-relativity) and the 43" seconds of arc of advance of perihelion of Planet mercury (general-relativity) is are caused by deformed space-time physicists "thought" and not deformed space (x, y, z). Anyone dare to prove me wrong? E=mc²/2 E (Energy by definition) = mv²/2 = mc²/2; if v = c m = mass; v= speed; c= light speed; w= angular velocity; t= time S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects P = visual velocity = change of visual location P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t) = (v + ì w r) Exp (ì w t) = v (1 + ì) Exp (ì w t) = visual speed; v = w r E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2 = m p²/2 = m v²/2 (1 + ì) ² Exp (2ì wt) = mv²/2 (2ì) [cosine (2wt) + ì sine (2wt)] =ì mv² [1 - 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed wt = π/2 E (visual) = ìmv² (1 - 2 + 0) E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c w t = π/4 E (visual) = imv² [1-1 +ỉ] =-mc²; v = c wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 - ln2 Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)] E (visual) = imv² (-ỉ/2) =1/2mc² v = c Conclusion: E = mc² is the visual Illusion of E = mc²/2 joenahhas1958@yahoo.com. All rights reserved. PS: In case of E=mc² claims to be rest energy claims then E=1/2m (m v + m' r) ² = (1/2m) (m' r) ²; v = 0 E = (1/2m) (mc) ²; m' r =mc E=mc²/2 Space-time to the sewer------------------------------------------>

Unregistered user Tuesday, February 3, 2009 2:25:13 AM

Anonymous writes: There is One and Only One Mechanics: Universal Mechanics: Ending Einstein's space-jail of time in 2009 joenahhas1958@yahoo.com Introduction to Universal Mechanics: For 350 years Physicists Astronomers and Mathematicians missed Kepler's time dependent equation introduced here and transformed Newton's equation into a time dependent Newton' equation and together these two equations explain Quantum - Relativistic effects; it combines classical mechanics and quantum mechanics into one mechanics and explains "relativistic" effects as the difference between time dependent measurements and time independent measurements of moving objects. Time is not a structure like space to scientifically accept space-to imaginary time - back to space jumping continuum (x, y, z, it) regardless of what all 100,000 living space-time physicists and Astrophysicists have said about it because Physics is a business and not necessarily science or scientific and like every business Physics comes with fraud and fraud is "junk" experimentation and junk based "thought" experimentation that led to fraud physics E=mc². All there is in the Universe is objects of mass m moving in space (x, y, z) at a location r = r (x, y, z). The state of any object in the Universe can be expressed as the product S = m r; State = mass x location: P = d S/d t = m (d r/dt) + (dm/dt) r = Total moment = change of location + change of mass = m v + m' r; v = velocity = d r/d t; m' = mass change rate F = d P/d t = d²S/dt² = Total force = m(d²r/dt²) +2(dm/dt)(d r/d t) + (d²m/dt²)r = mγ + 2m'v +m"r; γ = acceleration; m'' = mass acceleration rate In polar coordinates system r = r r(1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + rθ")θ(1) F = m[(r"-rθ'²)r(1) + (2r'θ' + rθ")θ(1)] + 2m'[r'r(1) + rθ'θ(1)] + (m"r) r(1) = [d²(mr)/dt² - (mr)θ'²]r(1) + (1/mr)[d(m²r²θ')/dt]θ(1) = [-GmM/r²]r(1) d²(mr)/dt² - (mr)θ'² = -GmM/r² Newton's Gravitational Equation (1) d(m²r²θ')/dt = 0 Central force law (2) (2) : d(m²r²θ')/d t = 0 <==> m²r²θ' = [m²(θ,0)φ²(0,t)][ r²(θ,0)ψ²(0,t)][θ'(θ, t)] = [m²(θ,t)][r²(θ,t)][θ'(θ,t)] = [m²(θ,0)][r²(θ,0)][θ'(θ,0)] = [m²(θ,0)]h(θ,0);h(θ,0)=[r²(θ,0)][θ'(θ,0)] = H (0, 0) = m² (0, 0) h (0, 0) = m² (0, 0) r² (0, 0) θ'(0, 0) m = m (θ, 0) φ (0, t) = m (θ, 0) Exp [λ (m) + ì ω (m)] t; Exp = Exponential φ (0, t) = Exp [ λ (m) + ỉ ω (m)]t r = r(θ,0) ψ(0, t) = r(θ,0) Exp [λ(r) + ì ω(r)]t ψ(0, t) = Exp [λ(r) + ỉ ω (r)]t θ'(θ, t) = {H(0, 0)/[m²(θ,0) r(θ,0)]}Exp{-2{[λ(m) + λ(r)]t + ì [ω(m) + ω(r)]t}} ------I Kepler's time dependent equation that Physicists Astrophysicists and Mathematicians missed for 350 years that is going to demolish Einstein's space-jail of time θ'(0,t) = θ'(0,0) Exp{-2{[λ(m) + λ(r)]t + ỉ[ω(m) + ω(r)]t}} (1): d² (m r)/dt² - (m r) θ'² = -GmM/r² = -Gm³M/m²r² d² (m r)/dt² - (m r) θ'² = -Gm³ (θ, 0) φ³ (0, t) M/ (m²r²) Let m r =1/u d (m r)/d t = -u'/u² = -(1/u²)(θ')d u/d θ = (- θ'/u²)d u/d θ = -H d u/d θ d²(m r)/dt² = -Hθ'd²u/dθ² = - Hu²[d²u/dθ²] -Hu² [d²u/dθ²] -(1/u)(Hu²)² = -Gm³(θ,0)φ³(0,t)Mu² [d²u/ dθ²] + u = Gm³(θ,0)φ³(0,t)M/H² t = 0; φ³ (0, 0) = 1 u = Gm³(θ,0)M/H² + Acosθ =Gm(θ,0)M(θ,0)/h²(θ,0) mr = 1/u = 1/[Gm(θ,0)M(θ,0)/h(θ,0) + Acosθ] = [h²/Gm(θ,0)M(θ,0)]/{1 + [Ah²/Gm(θ,0)M(θ,0)][cosθ]} = [h²/Gm(θ,0)M(θ,0)]/(1 + εcosθ) mr = [a(1-ε²)/(1+εcosθ)]m(θ,0) r(θ,0) = [a(1-ε²)/(1+εcosθ)] m r = m(θ, t) r(θ, t) = m(θ,0)φ(0,t)r(θ,0)ψ(0,t) r(θ,t) = [a(1-ε²)/(1+εcosθ)]{Exp[λ(r)+ω(r)]t} Newton's time dependent Equation --------II If λ (m) ≈ 0 fixed mass and λ(r) ≈ 0 fixed orbit; then θ'(0,t) = θ'(0,0) Exp{-2ì[ω(m) + ω(r)]t} r(θ, t) = r(θ,0) r(0,t) = [a(1-ε²)/(1+εcosθ)] Exp m = m(θ,0) Exp = m(0,0) Exp [ỉ ω(m) t] ; m(0,0) θ'(0,t) = θ'(0, 0) Exp {-2ì[ω(m) + ω(r)]t} θ'(0,0)=h(0,0)/r²(0,0)=2πab/Ta²(1-ε)² = 2πa² [√ (1-ε²)]/T a² (1-ε) ²; θ'(0, 0) = 2π [√ (1-ε²)]/T (1-ε) ² θ'(0,t) = {2π[√(1-ε²)]/T(1-ε)²}Exp{-2[ω(m) + ω(r)]t θ'(0,t) = {2π[√(1-ε²)]/(1-ε)²}{cos 2[ω(m) + ω(r)]t - ỉ sin 2[ω(m) + ω(r)]t} θ'(0,t) = θ'(0,0) {1- 2sin² [ω(m) + ω(r)]t - ỉ 2isin [ω(m) + ω(r)]t cos [ω(m) + ω(r)]t} θ'(0,t) = θ'(0,0){1 - 2[sin ω(m)t cos ω(r)t + cos ω(m) sin ω(r) t]²} - 2ỉ θ'(0, 0) sin [ω (m) + ω(r)] t cos [ω (m) + ω(r)] t Δ θ (0, t) = Real Δ θ (0, t) + Imaginary Δ θ (0.t) Real Δ θ (0, t) = θ'(0, 0) {1 - 2[sin ω (m) t cos ω(r) t + cos ω (m)t sin ω(r)t]²} W(ob) = Real Δ θ (0, t) - θ'(0, 0) = - 2 θ'(0, 0){(v°/c)√ [1-(v*/c) ²] + (v*/c)√ [1- (v°/c) ²]}² v ° = spin velocity; v* = orbital velocity; v°/c = sin ω (m)t; v*/c = cos ω (r) t v°/c << 1; (v°/c)² ≈ 0; v*/c << 1; (v*/c)² ≈ 0 W (ob) = - 2[2π √ (1-ε²)/T (1-ε) ²] [(v° + v*)/c] ² W (ob) = (- 4π /T) {[√ (1-ε²)]/ (1-ε) ²} [(v° + v*)/c] ² radians W (ob) = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} [(v° + v*)/c] ² degrees; Multiplication by 180/π W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²} [(v°+ v*)/c] ² degrees/100 years W” (ob) = (-720x26526x3600/T) {[√ (1-ε²)]/ (1-ε) ²} [(v° + v*)/c] ² seconds /100 years The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4) v (m) = √ [GM²/ (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system v (M) = √ [Gm² / (m + M)a(1-ε²/4)] ≈ 0; m<<M Application 3: Advance of Perihelion of mercury. G=6.673x10^-11; M=2x10^30kg; m=.32x10^24kg; ε = 0.206; T=88days c = 299792.458 km/sec; a = 58.2km/sec; 1-ε²/4 = 0.989391 ρ (m) = 0.696x10^9m; ρ(m)=2.44x10^6m; T(sun) = 25days v° (M) = 2km/sec ; v° = 2meters/sec v *= v(m) = √ [GM/a (1-ε²/4)]; v(M) = √[Gm²/(m + M)a(1-ε²)] ≈ 0 v°(m) = 2m/sec (Mercury) v°(M)= 2km/sec(sun) Calculations yields: v = v* + v° =48.14km/sec (mercury); [√ (1- ε²)] (1-ε) ² = 1.552 W" (ob) = (-720x36526x3600/T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² W" (ob) = (-720x36526x3600/88) x (1.552) (48.14/299792)² = 43.0”/century Application 4: Gravitational red shift: Pound Rebka Experiment r (θ, t) = r(θ, 0) Exp [î w(r)t] = λ(r) Exp[ỉ ω(r)t]; λ(r) = 0 1/r(θ, t) = 1/r(θ,0) = (1/λ) {Exp [-(î wt)]} υ (θ, t) = υ (θ,0) υ(0, t) = υ (θ, 0) Exp (-ì wt) = υ (θ, 0) [cos (ω t) + ỉ sin (ω t)] sin ω(r)t = v/c; cos ω(r)t = √[1-(v/c)²] υ (0,t) = υ(0,0){√[1-(v/c)²] + ỉ (v/c)} = Real {υ(0, t)} + Imaginary{υ(0, t)} Real {υ (0, t)} = υ (0, 0) √ [1-(v/c) ²] ≈ υ (0, 0) [1 - 1/2(v/c) ²] Δ υ (0, t) = real {υ (0, t)} - υ (0, 0) Δ υ (0, t) = -υ (0, 0)/2 [(v/c) ²] Δ υ(0, t)/υ(0, 0) = -1/2(v/c)²[up]-{1/2(v/c)²[down]} = - (v/c) ² v² = 2gh=2(9.806) (22.6m) Δ υ/υ [Total]=[2x9.806x22.6/299792.458]=4.93169x10^-15 Observed value: 5.1±5x10^-15 5- Light bending: Lord Eddington experiment θ' (θ, t) = θ' (θ, 0) θ'(0, t) = [h/r²(θ,0)] Exp { -2ỉ[ ω(m) + ω(r)]t}; ω (m) = 0 θ '(θ, t) = [2A/tr²(θ, 0)]{1 - 2sin²ω(r)t - 2ỉ sin ω(r)t cos ω(r)t} [t θ'(θ, t)] = [2A/r²(θ' 0)][1 - 2sin²ω(r)t] -2ỉ[2A/r²(θ, 0)][sin ω(r)t cos ω(r)t] = Δ x + i Δ y Δ θ = Δ x - [A/r² (θ, 0)] = - [A/r²(θ, 0)][4sin²ω(r)t]; sin ω(r)t = v/c Δ θ = - [A/r²(θ, 0)](v/c) ² (v/c)² ≈ 1.75"; v² = GM/R; G = Gravitational constant; M = Sun mass; R = sun radius Δ θ = [A/r²(θ, 0)] [1.75"]; A = area The values depend on near by stars and the measured values fit this equation. Russians in 1936; Δ θ = 2.74 [A/r² (θ, 0)] = π/2 Δ θ = π/2(1.75") = 2.74" Application 6: Shapiro time delay (Vikings 6, 7; 1977) Mars --------------------------- Middle---- Sun ------------- Earth The center of mass is the sun. The sun produces a velocity field given by v = √ [GM/a (1- ε²/4)] From above t =2 arc length/c=2d Δ w/c = (8π r/c) (v/c) ²; Δ w=4π (v/c) ²; r = 2a=d t = 16πGM/c³ (1-ε²/4); ε = [a (1) -a(2)]/[a(1) + a(2)] = .2075 t = (8πd/c) (v/c) ²= 8π (377,536,987.5/299792.458) (26.6575872/299792.458)²=250μs If d = 2a (1-ε²/4), then t = 247.597μs value theorized actual measured value is 250μs All this is not due to space-time but due to light aberration caused by moving planets. θ'(0,0) = h(0,0)/r²(0,0) = 2π/T θ' (0,t) = θ'(0,0)Exp(-2ỉwt)={2π/T} Exp (-2iwt) θ'(0,t) = θ'(0,0) [cosine 2(wt) - ỉ sine 2(wt)] = θ'(0,0) [1- 2sine² (wt) - ỉ sin 2(wt)] θ'(0,t) = θ'(0,t)(x) + θ'(0,t)(y); θ'(0,t)(x) = θ'(0,0)[ 1- 2sine² (wt)] θ'(0,t)(x) – θ'(0,0) = - 2θ'(0,0)sine²(wt) = - 2θ'(0,0)(v/c)² v/c=sine wt; c=light speed T [θ'(0, t) - θ'(0, 0)] = -4π (v/c) ²} Δ θ = -4π (v/c) ² Earth-Mars Sun-Photon: The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²---) ≈ 2πa (1-ε²/4); R =a (1-ε²/4) v=√ [Gm M/ (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system ΔΓ = 2 arc length/c = 2[Δ θ] 2d/c = 2[- 4π (v/c) ²] 2d/c; ΔΓ = -8πd/c (v/c) ²; ΔΓ = 8πd/c³ [GM/a (1-ε²/4)] =16πGM/c³ (1-ε²/4) = Γ0 (1 - ε²/4) ε = [a (planet 1) - a (planet 2)]/ [a (planet 1) + a (planet 2)] =0.2075 Mars-Earth Γ0 = 16 πGM/c³= 247.5974607μs=universal constant; ΔΓ = 250μs Mars-Earth.

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