Feature Not yet Implemented

(define (abs x)
  (cond ((> x 0) x)
	((= x 0) 0)
	((< x 0) (- x))))

; Exercise 1.3
; Take three numbers and return the sum of
; the squares of the two larger numbers

(define (sq x)
  (* x x))

(define (sumqs a b c)
  (cond ((and (> a c) (> b c)) (+ (sq a) (sq b)))
        ))

(sumqs 5 6 1)