编程实现将任意的十进制整数转换成R进制数(R在2-16之间)。
Friday, August 11, 2006 3:21:56 PM
#include<stdio.h>
#include<conio.h>
int main(void)
{
int n,R,i=0,a[16]={0};
char str[17]="0123456789ABCDEF";
printf("please input an integer number:\n");
scanf("%d",&n);
printf("please input R:\n");
scanf("%d",&R);
if(n<0)
{
printf("%c",'-');
n=-n;
}
while(n!=0)
{
a[i++]=n%R;
n=n/R;
}
while(i-->0)
printf("%c",str[a]);
getche();
}
#include<conio.h>
int main(void)
{
int n,R,i=0,a[16]={0};
char str[17]="0123456789ABCDEF";
printf("please input an integer number:\n");
scanf("%d",&n);
printf("please input R:\n");
scanf("%d",&R);
if(n<0)
{
printf("%c",'-');
n=-n;
}
while(n!=0)
{
a[i++]=n%R;
n=n/R;
}
while(i-->0)
printf("%c",str[a]);
getche();
}









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